Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:31Z
∇²n = 0
∫₀^∞ e^(-α²) dα = √π / 2
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9r² + 4r + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∑_{k=1}^{n} k = n(n+1)/2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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11γ² + 3γ + 6 = 0
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 4 2 ; 6 5 | = 8
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det| 6 1 ; 3 7 | = 39
∑_{k=1}^{n} k = n(n+1)/2
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det| 7 4 ; 4 8 | = 40
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