Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 23:10Z
11t² + 8t + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
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∂ω/∂β = 7ω
∑_{k=1}^{n} k = n(n+1)/2
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det| 3 3 ; 7 4 | = -9
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
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det| 7 4 ; 4 8 | = 40
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