Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:19Z

11n² + 5n + 4 = 0

∇ × E = −∂B/∂t

460K

8ψ² + 7ψ + 0 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

4φ² + 6φ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

448K

det| 10 7 ; 3 11 | = 89

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

e^{i\pi} + 1 = 0

459K

12y² + 5y + 7 = 0

406K

PV = nRT

181K

E = mc²

80K

d/dt [t^3] = 3t^2

359K

\lim_{β\to 0} \frac{\sin β}{β} = 1

455K