Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:18Z

11n² + 5n + 4 = 0

∇²t = 0

460K

F = G m₁m₂ / r²

438K

∫₀^∞ e^(-x²) dx = √π / 2

CH₄ + 2O₂ → CO₂ + 2H₂O

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

11φ² + 4φ + 0 = 0

448K

e^{i\pi} + 1 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∇ × E = −∂B/∂t

459K

11t² + 9t + 7 = 0

406K

∇²ω = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

det| 7 4 ; 4 8 | = 40

80K

d/dr [r^2] = 2r^1

ΔS ≥ 0

8β² + 5β + 0 = 0

det| 12 6 ; 6 13 | = 120