Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-21 11:08Z

e^{i\pi} + 1 = 0

E = mc²

195K

N₂ + 3H₂ ⇌ 2NH₃

262K

∇²y = 0

5z² + 8z + 3 = 0

iħ ∂ψ/∂t = Ĥψ

244K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

∑_{k=1}^{n} k = n(n+1)/2

231K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

26K

N₂ + 3H₂ ⇌ 2NH₃

∑_{k=1}^{n} k = n(n+1)/2

209K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

331K

det| 7 4 ; 4 8 | = 40

163K