Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:48Z
∇²n = 0
∫₀^∞ e^(-z²) dz = √π / 2
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9r² + 4r + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
11γ² + 3γ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-α²) dα = √π / 2
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det| 7 9 ; 1 8 | = 47
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