Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 12:21Z

∑_{k=1}^{n} k = n(n+1)/2

8ψ² + 7ψ + 0 = 0

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

4y² + 7y + 7 = 0

d/dx [x^9] = 9x^8

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det| 4 8 ; 3 5 | = -4

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∇²t = 0

iħ ∂ψ/∂t = Ĥψ

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det| 5 2 ; 6 6 | = 18

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6β² + 2β + 2 = 0

N₂ + 3H₂ ⇌ 2NH₃

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e^{i\pi} + 1 = 0

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2φ² + 2φ + 5 = 0

PV = nRT

181K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\lim_{n\to 0} \frac{\sin n}{n} = 1

9ψ² + 7ψ + 3 = 0

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