Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:18Z

∇²n = 0

∇²ω = 0

273K

6ω² + 4ω + 4 = 0

263K

9r² + 4r + 1 = 0

∫₀^∞ e^(-ω²) dω = √π / 2

139K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

8ψ² + 7ψ + 0 = 0

333K

iħ ∂ψ/∂t = Ĥψ

160K

11γ² + 3γ + 6 = 0

\frac{2}{2} \sum_{i=1}^{n} i^{2}

439K

CH₄ + 2O₂ → CO₂ + 2H₂O

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

10t² + 9t + 5 = 0

297K

det| 10 2 ; 3 11 | = 104

128K

N₂ + 3H₂ ⇌ 2NH₃

404K