Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:21Z

∇²n = 0

N₂ + 3H₂ ⇌ 2NH₃

273K

6x² + 6x + 1 = 0

263K

9r² + 4r + 1 = 0

ω = 2πf

139K

d/dt [t^3] = 3t^2

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

333K

\frac{4}{9} \sum_{i=1}^{n} i^{2}

160K

11γ² + 3γ + 6 = 0

∇²ω = 0

439K

det| 10 7 ; 3 11 | = 89

413K

9θ² + 7θ + 4 = 0

297K

det| 9 4 ; 1 10 | = 86

128K