Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:17Z

10γ² + 4γ + 3 = 0

∇ × E = −∂B/∂t

460K

2H₂ + O₂ → 2H₂O

438K

d/dβ [β^11] = 11β^10

∑_{k=1}^{n} k = n(n+1)/2

186K

12y² + 5y + 7 = 0

411K

3x² + 4x + 6 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

22K

8ψ² + 7ψ + 0 = 0

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

d/dt [t^3] = 3t^2

181K

det| 10 2 ; 3 11 | = 104

80K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

359K

E = mc²

455K