Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 16:41Z
10γ² + 4γ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
d/dβ [β^11] = 11β^10
Fe₂O₃ + 3CO → 2Fe + 3CO₂
411K
3x² + 4x + 6 = 0
CaCO₃ → CaO + CO₂
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
F = ma
3n² + 3n + 5 = 0