Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:36Z

11t² + 8t + 0 = 0

e^{i\pi} + 1 = 0

460K

8x² + 2x + 7 = 0

438K

∂ω/∂β = 7ω

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

F = ma

411K

det| 3 3 ; 7 4 | = -9

Fe₂O₃ + 3CO → 2Fe + 3CO₂

448K

8ψ² + 7ψ + 0 = 0

22K

PV = nRT

d/dt [t^3] = 3t^2

459K

11t² + 9t + 5 = 0

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

181K

∇ × E = −∂B/∂t

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