Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 22:05Z
3n² + 7n + 7 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∫₀^∞ e^(-ω²) dω = √π / 2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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det| 7 2 ; 7 8 | = 42
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\frac{10}{6} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
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\lim_{β\to 0} \frac{\sin β}{β} = 1
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det| 3 1 ; 7 4 | = 5
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det| 9 4 ; 1 10 | = 86
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