Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:40Z

∑_{k=1}^{n} k = n(n+1)/2

iħ ∂ψ/∂t = Ĥψ

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det| 5 6 ; 2 6 | = 18

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det| 8 9 ; 3 9 | = 45

6n² + 7n + 6 = 0

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12y² + 5y + 7 = 0

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

d/dt [t^3] = 3t^2

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11t² + 9t + 7 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

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∇²ω = 0

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det| 9 4 ; 1 10 | = 86

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\frac{8}{7} \sum_{i=1}^{n} i^{2}

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