Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:54Z

d/dy [y^8] = 8y^7

6r² + 3r + 1 = 0

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CH₄ + 2O₂ → CO₂ + 2H₂O

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\lim_{x\to 0} \frac{\sin x}{x} = 1

iħ ∂ψ/∂t = Ĥψ

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∇ × E = −∂B/∂t

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d/dn [n^3] = 3n^2

CH₄ + 2O₂ → CO₂ + 2H₂O

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d/dt [t^3] = 3t^2

411K

∑_{k=1}^{n} k = n(n+1)/2

377K

7y² + 9y + 1 = 0

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8ψ² + 7ψ + 0 = 0

401K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

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