Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:51Z

det| 5 4 ; 6 6 | = 6

∇ × E = −∂B/∂t

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\oint_C \vec{F}\cdot d\vec{r} = 0

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∇²φ = 0

∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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det| 12 5 ; 4 13 | = 136

8ψ² + 7ψ + 0 = 0

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∂n/∂θ = 3n

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∑_{k=1}^{n} k = n(n+1)/2

d/dt [t^3] = 3t^2

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∂y/∂n = 5y

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6t² + 6t + 4 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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11φ² + 4φ + 0 = 0

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