Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 17:21Z

det| 11 2 ; 2 12 | = 128

N₂ + 3H₂ ⇌ 2NH₃

460K

∫₀^∞ e^(-t²) dt = √π / 2

438K

CaCO₃ → CaO + CO₂

det| 5 2 ; 3 6 | = 24

186K

iħ ∂ψ/∂t = Ĥψ

411K

3θ² + 7θ + 1 = 0

F = ma

448K

8ψ² + 7ψ + 0 = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

d/dx [x^3] = 3x^2

459K

\lim_{r\to 0} \frac{\sin r}{r} = 1

406K

2H₂ + O₂ → 2H₂O

∇ × E = −∂B/∂t

∫₀^∞ e^(-z²) dz = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O