Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:42Z

d/dy [y^8] = 8y^7

∑_{k=1}^{n} k = n(n+1)/2

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∇²ω = 0

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\lim_{x\to 0} \frac{\sin x}{x} = 1

∇²ω = 0

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det| 11 9 ; 0 12 | = 132

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d/dn [n^3] = 3n^2

8ψ² + 7ψ + 0 = 0

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6ω² + 4ω + 4 = 0

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6t² + 4t + 0 = 0

d/dt [t^3] = 3t^2

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\frac{4}{6} \sum_{i=1}^{n} i^{2}

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e^{i\pi} + 1 = 0

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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∇ × E = −∂B/∂t

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