Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:48Z

det| 6 5 ; 4 7 | = 22

\lim_{r\to 0} \frac{\sin r}{r} = 1

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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∇²φ = 0

∂y/∂n = 5y

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F = G m₁m₂ / r²

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\frac{9}{2} \sum_{i=1}^{n} i^{2}

∇ × E = −∂B/∂t

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det| 9 8 ; 3 10 | = 66

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F = ma

PV = nRT

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det| 7 4 ; 4 8 | = 40

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ΔS ≥ 0

∇ × E = −∂B/∂t

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