Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:56Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

F = G m₁m₂ / r²

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²n = 0

186K

det| 12 2 ; 2 13 | = 152

411K

4φ² + 6φ + 2 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

448K

e^{i\pi} + 1 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 2 6 ; 0 3 | = 6

459K

det| 9 4 ; 1 10 | = 86

406K

∇²ω = 0

∑_{k=1}^{n} k = n(n+1)/2

181K

iħ ∂ψ/∂t = Ĥψ

80K

d/dr [r^2] = 2r^1

\lim_{β\to 0} \frac{\sin β}{β} = 1

359K

ΔS ≥ 0

8β² + 5β + 0 = 0

det| 12 6 ; 6 13 | = 120