Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:49Z

3γ² + 8γ + 4 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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∫₀^∞ e^(-t²) dt = √π / 2

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PV = nRT

∇ × E = −∂B/∂t

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F = G m₁m₂ / r²

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det| 1 9 ; 5 2 | = -43

\lim_{α\to 0} \frac{\sin α}{α} = 1

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5z² + 8z + 3 = 0

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ω = 2πf

∑_{k=1}^{n} k = n(n+1)/2

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CaCO₃ → CaO + CO₂

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∂α/∂ω = 3α

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det| 7 4 ; 4 8 | = 40

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