Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 05:21Z

λ = h/p

3x² + 5x + 7 = 0

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∇ × E = −∂B/∂t

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det| 3 9 ; 5 4 | = -33

∇²n = 0

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6t² + 6t + 4 = 0

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iħ ∂ψ/∂t = Ĥψ

∇²θ = 0

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d/dt [t^3] = 3t^2

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det| 8 7 ; 0 9 | = 72

det| 4 7 ; 2 5 | = 6

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

8ψ² + 7ψ + 0 = 0

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det| 10 2 ; 3 11 | = 104

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∇ × E = −∂B/∂t

404K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

58K