Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:33Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 7 4 ; 4 8 | = 40

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∫₀^∞ e^(-x²) dx = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

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ω = 2πf

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4φ² + 6φ + 2 = 0

12y² + 5y + 7 = 0

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\lim_{α\to 0} \frac{\sin α}{α} = 1

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∫₀^∞ e^(-φ²) dφ = √π / 2

\frac{12}{6} \sum_{i=1}^{n} i^{2}

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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∇²ω = 0

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