Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 22:11Z

3n² + 7n + 7 = 0

∫₀^∞ e^(-t²) dt = √π / 2

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-ω²) dω = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

det| 9 5 ; 1 10 | = 85

411K

\frac{10}{6} \sum_{i=1}^{n} i^{2}

N₂ + 3H₂ ⇌ 2NH₃

448K

det| 7 4 ; 4 8 | = 40

22K

2n² + 4n + 0 = 0

459K

d/dx [x^3] = 3x^2

406K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K