Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:10Z

10y² + 2y + 6 = 0

∇²β = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-t²) dt = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

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det| 7 4 ; 4 8 | = 40

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e^{i\pi} + 1 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

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det| 12 1 ; 5 13 | = 151

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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10ψ² + 5ψ + 0 = 0

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∇ × E = −∂B/∂t

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N₂ + 3H₂ ⇌ 2NH₃

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F = G m₁m₂ / r²

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