Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 11:44Z
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
det| 6 4 ; 3 7 | = 30
ΔS ≥ 0
1z² + 3z + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
459K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
406K
7t² + 3t + 1 = 0
det| 7 4 ; 4 8 | = 40
181K
det| 11 5 ; 2 12 | = 122
det| 8 3 ; 4 9 | = 60
10γ² + 8γ + 2 = 0
∇ × E = −∂B/∂t
λ = h/p