Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:44Z

d/dy [y^8] = 8y^7

∑_{k=1}^{n} k = n(n+1)/2

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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\lim_{x\to 0} \frac{\sin x}{x} = 1

∑_{k=1}^{n} k = n(n+1)/2

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∇²β = 0

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d/dn [n^3] = 3n^2

det| 9 4 ; 1 10 | = 86

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d/dt [t^3] = 3t^2

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2n² + 4n + 0 = 0

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∇²z = 0

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∂y/∂γ = 8y

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