Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:15Z

∇²n = 0

∑_{k=1}^{n} k = n(n+1)/2

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8ψ² + 7ψ + 0 = 0

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9r² + 4r + 1 = 0

det| 11 4 ; 5 12 | = 112

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∇ × E = −∂B/∂t

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d/dt [t^3] = 3t^2

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11γ² + 3γ + 6 = 0

7y² + 9y + 1 = 0

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∇²t = 0

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\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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