Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:52Z

3γ² + 8γ + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

PV = nRT

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

iħ ∂ψ/∂t = Ĥψ

411K

det| 1 9 ; 5 2 | = -43

∑_{k=1}^{n} k = n(n+1)/2

448K

det| 7 4 ; 4 8 | = 40

22K

ω = 2πf

\lim_{r\to 0} \frac{\sin r}{r} = 1

459K

10ω² + 7ω + 4 = 0

406K

∂n/∂ψ = 6n

∫₀^∞ e^(-ψ²) dψ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃