Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:43Z

3γ² + 8γ + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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11φ² + 4φ + 0 = 0

438K

PV = nRT

\lim_{r\to 0} \frac{\sin r}{r} = 1

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det| 7 2 ; 7 8 | = 42

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det| 1 9 ; 5 2 | = -43

∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-α²) dα = √π / 2

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F = G m₁m₂ / r²

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇²β = 0

181K

N₂ + 3H₂ ⇌ 2NH₃

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det| 7 4 ; 4 8 | = 40

359K