Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:03Z

11n² + 5n + 4 = 0

det| 11 5 ; 0 12 | = 132

460K

d/dt [t^3] = 3t^2

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇ × E = −∂B/∂t

186K

ω = 2πf

411K

4φ² + 6φ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

det| 4 2 ; 6 5 | = 8

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

1n² + 7n + 3 = 0

459K

∫₀^∞ e^(-x²) dx = √π / 2

406K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

8ψ² + 7ψ + 0 = 0

80K

PV = nRT

359K

∇²r = 0

455K