Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:41Z
10y² + 2y + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
460K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
438K
∫₀^∞ e^(-t²) dt = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
186K
e^{i\pi} + 1 = 0
\frac{2}{2} \sum_{i=1}^{n} i^{2}
448K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
22K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 1 4 ; 3 2 | = -10
406K
λ = h/p
det| 9 4 ; 1 10 | = 86
181K
∑_{k=1}^{n} k = n(n+1)/2
80K
d/dγ [γ^3] = 3γ^2