Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:15Z

∇²n = 0

det| 7 4 ; 4 8 | = 40

273K

∇²θ = 0

263K

9r² + 4r + 1 = 0

det| 9 5 ; 1 10 | = 85

139K

F = G m₁m₂ / r²

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\binom{n}{k} = \frac{n!}{k!(n-k)!}

333K

det| 4 2 ; 6 5 | = 8

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11γ² + 3γ + 6 = 0

∇ × E = −∂B/∂t

439K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

413K

∇ × E = −∂B/∂t

297K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

128K