Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 11:44Z
∇²t = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
460K
∑_{k=1}^{n} k = n(n+1)/2
438K
det| 6 4 ; 3 7 | = 30
∫₀^∞ e^(-r²) dr = √π / 2
186K
CH₄ + 2O₂ → CO₂ + 2H₂O
411K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
448K
1z² + 3z + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
459K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
406K
7t² + 3t + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
359K