Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:48Z

∇²n = 0

∑_{k=1}^{n} k = n(n+1)/2

273K

iħ ∂ψ/∂t = Ĥψ

263K

9r² + 4r + 1 = 0

8ψ² + 7ψ + 0 = 0

139K

ω = 2πf

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

10ψ² + 5ψ + 0 = 0

333K

CH₄ + 2O₂ → CO₂ + 2H₂O

160K

11γ² + 3γ + 6 = 0

N₂ + 3H₂ ⇌ 2NH₃

439K

E = mc²

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

iħ ∂ψ/∂t = Ĥψ

297K

\lim_{α\to 0} \frac{\sin α}{α} = 1

128K

det| 6 1 ; 3 7 | = 39

∂α/∂ω = 3α

404K

e^{i\pi} + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

∑_{k=1}^{n} k = n(n+1)/2