Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 23:38Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

10t² + 9t + 5 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

10γ² + 8γ + 7 = 0

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iħ ∂ψ/∂t = Ĥψ

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ω = 2πf

CH₄ + 2O₂ → CO₂ + 2H₂O

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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e^{i\pi} + 1 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

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2H₂ + O₂ → 2H₂O

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det| 7 4 ; 4 8 | = 40

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∇²n = 0

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

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