Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 19:34Z

CH₄ + 2O₂ → CO₂ + 2H₂O

6t² + 6t + 4 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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det| 1 1 ; 4 2 | = -2

10γ² + 8γ + 7 = 0

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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CaCO₃ → CaO + CO₂

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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8ψ² + 7ψ + 0 = 0

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det| 8 4 ; 2 9 | = 64

N₂ + 3H₂ ⇌ 2NH₃

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iħ ∂ψ/∂t = Ĥψ

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9ψ² + 7ψ + 3 = 0

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