Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:33Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

det| 7 4 ; 4 8 | = 40

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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\frac{8}{4} \sum_{i=1}^{n} i^{2}

∇ × E = −∂B/∂t

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6x² + 6x + 1 = 0

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N₂ + 3H₂ ⇌ 2NH₃

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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F = ma

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2α² + 3α + 3 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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PV = nRT

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2H₂ + O₂ → 2H₂O

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F = G m₁m₂ / r²

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∇²r = 0

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