Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 01:37Z

11φ² + 9φ + 3 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∫₀^∞ e^(-z²) dz = √π / 2

438K

∫₀^∞ e^(-y²) dy = √π / 2

iħ ∂ψ/∂t = Ĥψ

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8ψ² + 7ψ + 0 = 0

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\lim_{y\to 0} \frac{\sin y}{y} = 1

det| 7 6 ; 1 8 | = 50

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det| 2 8 ; 7 3 | = -50

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CaCO₃ → CaO + CO₂

iħ ∂ψ/∂t = Ĥψ

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

∑_{k=1}^{n} k = n(n+1)/2

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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d/dx [x^3] = 3x^2

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F = G m₁m₂ / r²

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