Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:42Z
det| 6 5 ; 4 7 | = 22
det| 3 7 ; 2 4 | = -2
460K
∇²φ = 0
\frac{9}{2} \sum_{i=1}^{n} i^{2}
det| 2 3 ; 5 3 | = -9
22K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
459K
ΔS ≥ 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-θ²) dθ = √π / 2
359K
1φ² + 4φ + 5 = 0