Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:19Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇ × E = −∂B/∂t

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∫₀^∞ e^(-x²) dx = √π / 2

det| 11 4 ; 5 12 | = 112

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5z² + 8z + 3 = 0

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4φ² + 6φ + 2 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

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∫₀^∞ e^(-θ²) dθ = √π / 2

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∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

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iħ ∂ψ/∂t = Ĥψ

406K

det| 7 4 ; 4 8 | = 40

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det| 8 9 ; 4 9 | = 36

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F = G m₁m₂ / r²

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F = G m₁m₂ / r²

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