Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:53Z

11n² + 5n + 4 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

6x² + 6x + 1 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

11t² + 9t + 5 = 0

186K

e^{i\pi} + 1 = 0

411K

4φ² + 6φ + 2 = 0

8x² + 2x + 7 = 0

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 7 4 ; 4 8 | = 40

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

∇²ω = 0

det| 3 7 ; 2 4 | = -2

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

e^{i\pi} + 1 = 0

359K

det| 10 2 ; 3 11 | = 104

455K