Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:39Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

186K

CH₄ + 2O₂ → CO₂ + 2H₂O

411K

4φ² + 6φ + 2 = 0

det| 7 4 ; 4 8 | = 40

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

4t² + 3t + 3 = 0

459K

∇²θ = 0

406K

∇²β = 0

181K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

80K

11t² + 9t + 5 = 0

359K