Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 18:29Z

e^{i\pi} + 1 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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λ = h/p

8ψ² + 7ψ + 0 = 0

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det| 5 9 ; 7 6 | = -33

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det| 6 7 ; 7 7 | = -7

∇ × E = −∂B/∂t

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∑_{k=1}^{n} k = n(n+1)/2

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∇²ψ = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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iħ ∂ψ/∂t = Ĥψ

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∂γ/∂γ = 9γ

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

E = mc²