Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:41Z

11n² + 5n + 4 = 0

det| 5 6 ; 2 6 | = 18

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²γ = 0

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

4φ² + 6φ + 2 = 0

det| 7 4 ; 4 8 | = 40

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-φ²) dφ = √π / 2

iħ ∂ψ/∂t = Ĥψ

459K

F = G m₁m₂ / r²

406K

det| 1 4 ; 3 2 | = -10

181K

∫₀^∞ e^(-t²) dt = √π / 2

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