Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:01Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 7 4 ; 4 8 | = 40

186K

11t² + 9t + 7 = 0

411K

4φ² + 6φ + 2 = 0

6n² + 7n + 6 = 0

448K

det| 3 1 ; 7 4 | = 5

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∫₀^∞ e^(-t²) dt = √π / 2

459K

∂α/∂ω = 3α

406K

\lim_{r\to 0} \frac{\sin r}{r} = 1

181K