Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:38Z

N₂ + 3H₂ ⇌ 2NH₃

∑_{k=1}^{n} k = n(n+1)/2

246K

det| 7 4 ; 4 8 | = 40

118K

9ψ² + 4ψ + 2 = 0

8x² + 2x + 7 = 0

43K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

261K

d/dβ [β^6] = 6β^5

\lim_{t\to 0} \frac{\sin t}{t} = 1

424K

∫₀^∞ e^(-θ²) dθ = √π / 2

76K

det| 6 1 ; 4 7 | = 38

6x² + 6x + 1 = 0

41K

N₂ + 3H₂ ⇌ 2NH₃

298K

\frac{6}{5} \sum_{i=1}^{n} i^{2}

5ψ² + 8ψ + 3 = 0