Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:51Z

det| 5 4 ; 6 6 | = 6

∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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∇²φ = 0

det| 9 4 ; 1 10 | = 86

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N₂ + 3H₂ ⇌ 2NH₃

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det| 12 5 ; 4 13 | = 136

d/dt [t^3] = 3t^2

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iħ ∂ψ/∂t = Ĥψ

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4t² + 3t + 3 = 0

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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∂γ/∂θ = 2γ

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

359K