Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:35Z

11n² + 5n + 4 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

2H₂ + O₂ → 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

PV = nRT

411K

4φ² + 6φ + 2 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

448K

\lim_{t\to 0} \frac{\sin t}{t} = 1

22K

8ψ² + 7ψ + 0 = 0

459K

CH₄ + 2O₂ → CO₂ + 2H₂O

406K

iħ ∂ψ/∂t = Ĥψ

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

E = mc²

359K

10t² + 9t + 5 = 0

455K