Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:17Z

∑_{k=1}^{n} k = n(n+1)/2

8ψ² + 7ψ + 0 = 0

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e^{i\pi} + 1 = 0

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det| 8 9 ; 3 9 | = 45

d/dt [t^3] = 3t^2

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∇²γ = 0

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

det| 11 4 ; 5 12 | = 112

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∇ × E = −∂B/∂t

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∫₀^∞ e^(-θ²) dθ = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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